Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation 2x^2-8=0
-
Equation 16*x^2/5-5=0
-
Equation x^2+14*x+40=0
-
Equation x^2-18=7x
- Express {x} in terms of y where:
- 12*x+2*y=-9
- 2*x+6*y=-2
- -19*x-16*y=3
- -18*x+10*y=12
- Integral of d{x}:
- 1-1/x^2
- Derivative of:
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1-1/x^2
- Sum of series:
- 1-1/x^2
-
Identical expressions
- one - one /x^ two = zero
- 1 minus 1 divide by x squared equally 0
- one minus one divide by x to the power of two equally zero
- 1-1/x2=0
- 1-1/x²=0
- 1-1/x to the power of 2=0
- 1-1/x^2=O
- 1-1 divide by x^2=0
-
Similar expressions
- 1+1/x^2=0
1-1/x^2=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$1 - \frac{1}{x^{2}} = 0$$
Because equation degree is equal to = -2 - contains the even number -2 in the numerator, then
the equation has two real roots.
Get the root -2-th degree of the equation sides:
We get:
$$\frac{1}{\sqrt{\frac{1}{x^{2}}}} = \frac{1}{\sqrt{1}}$$
$$\frac{1}{\sqrt{\frac{1}{x^{2}}}} = \left(-1\right) \frac{1}{\sqrt{1}}$$
or
$$x = 1$$
$$x = -1$$
We get the answer: x = 1
We get the answer: x = -1
or
$$x_{1} = -1$$
$$x_{2} = 1$$
The final answer:
$$x_{1} = -1$$
$$x_{2} = 1$$
$$1 - \frac{1}{x^{2}} = 0$$
Because equation degree is equal to = -2 - contains the even number -2 in the numerator, then
the equation has two real roots.
Get the root -2-th degree of the equation sides:
We get:
$$\frac{1}{\sqrt{\frac{1}{x^{2}}}} = \frac{1}{\sqrt{1}}$$
$$\frac{1}{\sqrt{\frac{1}{x^{2}}}} = \left(-1\right) \frac{1}{\sqrt{1}}$$
or
$$x = 1$$
$$x = -1$$
We get the answer: x = 1
We get the answer: x = -1
or
$$x_{1} = -1$$
$$x_{2} = 1$$
The final answer:
$$x_{1} = -1$$
$$x_{2} = 1$$
The graph