19*(y-9)=3*(y-8) equation
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The solution
Detail solution
Given the linear equation:
19*(y-9) = 3*(y-8)
Expand brackets in the left part
19*y-19*9 = 3*(y-8)
Expand brackets in the right part
19*y-19*9 = 3*y-3*8
Move free summands (without y)
from left part to right part, we given:
$$19 y = 3 y + 147$$
Move the summands with the unknown y
from the right part to the left part:
$$16 y = 147$$
Divide both parts of the equation by 16
y = 147 / (16)
We get the answer: y = 147/16
$$y_{1} = \frac{147}{16}$$
Sum and product of roots
[src]
$$\frac{147}{16}$$
$$\frac{147}{16}$$
$$\frac{147}{16}$$
$$\frac{147}{16}$$