9^x=27 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$9^{x} = 27$$
or
$$9^{x} - 27 = 0$$
or
$$9^{x} = 27$$
or
$$9^{x} = 27$$
- this is the simplest exponential equation
Do replacement
$$v = 9^{x}$$
we get
$$v - 27 = 0$$
or
$$v - 27 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 27$$
We get the answer: v = 27
do backward replacement
$$9^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(9 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(27 \right)}}{\log{\left(9 \right)}} = \frac{3}{2}$$
$$x_{1} = \frac{3}{2}$$
log(27) pi*I
x2 = -------- + ------
2*log(3) log(3)
$$x_{2} = \frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}}$$
x2 = log(27)/(2*log(3)) + i*pi/log(3)
Sum and product of roots
[src]
3 log(27) pi*I
- + -------- + ------
2 2*log(3) log(3)
$$\frac{3}{2} + \left(\frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}}\right)$$
3 log(27) pi*I
- + -------- + ------
2 2*log(3) log(3)
$$\frac{3}{2} + \frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}}$$
/log(27) pi*I \
3*|-------- + ------|
\2*log(3) log(3)/
---------------------
2
$$\frac{3 \left(\frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}}\right)}{2}$$
9 3*pi*I
- + --------
4 2*log(3)
$$\frac{9}{4} + \frac{3 i \pi}{2 \log{\left(3 \right)}}$$
x2 = 1.5 + 2.85960086738013*i
x2 = 1.5 + 2.85960086738013*i