9*x-72*√x=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$- 72 \sqrt{x} + 9 x = 0$$
Obviously:
x0 = 0
next,
transform
$$\sqrt{x} = 8$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{x}\right)^{2} = 8^{2}$$
or
$$x = 64$$
We get the answer: x = 64
The final answer:
x0 = 0
$$x_{1} = 64$$
$$x_{1} = 0$$
$$x_{2} = 64$$
Sum and product of roots
[src]
$$64$$
$$64$$
$$0 \cdot 64$$
$$0$$