Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 4+8x-5x^2=0
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Equation x+(8-3x)=12
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Equation (x^2+5x)/(x(x-2))=(6)/(x(x-2))
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Equation 3*x-4/6=7/8
- Express {x} in terms of y where:
- 16*x+14*y=-14
- 11*x-15*y=3
- 9*x-1*y=-2
- -13*x-15*y=9
- Integral of d{x}:
- |x+4|
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-2
- Graphing y =:
- |x+4|
- Sum of series:
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-2
- Derivative of:
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-2
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Identical expressions
- |x+ four |=- two
- module of x plus 4| equally minus 2
- module of x plus four | equally minus two
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Similar expressions
- |x+4|=+2
- |x-4|=-2
|x+4|=-2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 4 \geq 0$$
or
$$-4 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 4\right) + 2 = 0$$
after simplifying we get
$$x + 6 = 0$$
the solution in this interval:
$$x_{1} = -6$$
but x1 not in the inequality interval
2.
$$x + 4 < 0$$
or
$$-\infty < x \wedge x < -4$$
we get the equation
$$\left(- x - 4\right) + 2 = 0$$
after simplifying we get
$$- x - 2 = 0$$
the solution in this interval:
$$x_{2} = -2$$
but x2 not in the inequality interval
The final answer:
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 4 \geq 0$$
or
$$-4 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 4\right) + 2 = 0$$
after simplifying we get
$$x + 6 = 0$$
the solution in this interval:
$$x_{1} = -6$$
but x1 not in the inequality interval
2.
$$x + 4 < 0$$
or
$$-\infty < x \wedge x < -4$$
we get the equation
$$\left(- x - 4\right) + 2 = 0$$
after simplifying we get
$$- x - 2 = 0$$
the solution in this interval:
$$x_{2} = -2$$
but x2 not in the inequality interval
The final answer: