Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x+2)^2=(1-x)^2
-
Equation cos(x)=-2
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Equation x^2-3x-4=0
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Equation cos(x)=0
- Express {x} in terms of y where:
- -15*x+17*y=13
- 17*x-18*y=10
- 18*x+3*y=2
- -11*x+4*y=-8
- Derivative of:
- 7x-2
- Graphing y =:
- 7x-2
- Integral of d{x}:
- 7x-2
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Identical expressions
- | two x- seven |=7x-2
- module of 2x minus 7| equally 7x minus 2
- module of two x minus seven | equally 7x minus 2
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Similar expressions
- 2,5625*(x^2)+10-5*((x-1)^2)+16,771*((x-2)^2)-1,667*((x-2)^3)=0
- |2*x-7|=6
- |2x+7|=7x-2
- |2x-7|=7x+2
- sqrt(7*x^2+x-2)=sqrt(7*x-2)
- (x+3)(x-4)-(x-7)(x-2)=2
|2x-7|=7x-2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$2 x - 7 \geq 0$$
or
$$\frac{7}{2} \leq x \wedge x < \infty$$
we get the equation
$$- 7 x + \left(2 x - 7\right) + 2 = 0$$
after simplifying we get
$$- 5 x - 5 = 0$$
the solution in this interval:
$$x_{1} = -1$$
but x1 not in the inequality interval
2.
$$2 x - 7 < 0$$
or
$$-\infty < x \wedge x < \frac{7}{2}$$
we get the equation
$$- 7 x + \left(7 - 2 x\right) + 2 = 0$$
after simplifying we get
$$9 - 9 x = 0$$
the solution in this interval:
$$x_{2} = 1$$
The final answer:
$$x_{1} = 1$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$2 x - 7 \geq 0$$
or
$$\frac{7}{2} \leq x \wedge x < \infty$$
we get the equation
$$- 7 x + \left(2 x - 7\right) + 2 = 0$$
after simplifying we get
$$- 5 x - 5 = 0$$
the solution in this interval:
$$x_{1} = -1$$
but x1 not in the inequality interval
2.
$$2 x - 7 < 0$$
or
$$-\infty < x \wedge x < \frac{7}{2}$$
we get the equation
$$- 7 x + \left(7 - 2 x\right) + 2 = 0$$
after simplifying we get
$$9 - 9 x = 0$$
the solution in this interval:
$$x_{2} = 1$$
The final answer:
$$x_{1} = 1$$