|2*x-7|=11 equation
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The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$2 x - 7 \geq 0$$
or
$$\frac{7}{2} \leq x \wedge x < \infty$$
we get the equation
$$\left(2 x - 7\right) - 11 = 0$$
after simplifying we get
$$2 x - 18 = 0$$
the solution in this interval:
$$x_{1} = 9$$
2.
$$2 x - 7 < 0$$
or
$$-\infty < x \wedge x < \frac{7}{2}$$
we get the equation
$$\left(7 - 2 x\right) - 11 = 0$$
after simplifying we get
$$- 2 x - 4 = 0$$
the solution in this interval:
$$x_{2} = -2$$
The final answer:
$$x_{1} = 9$$
$$x_{2} = -2$$
$$x_{1} = -2$$
$$x_{2} = 9$$
Sum and product of roots
[src]
$$-2 + 9$$
$$7$$
$$- 18$$
$$-18$$