-x^2+8x+6=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
a*x^2 + b*x + c = 0 A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
x 1 = D − b 2 a x_{1} = \frac{\sqrt{D} - b}{2 a} x 1 = 2 a D − b x 2 = − D − b 2 a x_{2} = \frac{- \sqrt{D} - b}{2 a} x 2 = 2 a − D − b where D = b^2 - 4*a*c - it is the discriminant.
Because
a = − 1 a = -1 a = − 1 b = 8 b = 8 b = 8 c = 6 c = 6 c = 6 , then
D = b^2 - 4 * a * c = (8)^2 - 4 * (-1) * (6) = 88 Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a) x2 = (-b - sqrt(D)) / (2*a) or
x 1 = 4 − 22 x_{1} = 4 - \sqrt{22} x 1 = 4 − 22 Simplify x 2 = 4 + 22 x_{2} = 4 + \sqrt{22} x 2 = 4 + 22 Simplify
Vieta's Theorem
rewrite the equation
− x 2 + 8 x + 6 = 0 - x^{2} + 8 x + 6 = 0 − x 2 + 8 x + 6 = 0 of
a x 2 + b x + c = 0 a x^{2} + b x + c = 0 a x 2 + b x + c = 0 as reduced quadratic equation
x 2 + b x a + c a = 0 x^{2} + \frac{b x}{a} + \frac{c}{a} = 0 x 2 + a b x + a c = 0 x 2 − 8 x − 6 = 0 x^{2} - 8 x - 6 = 0 x 2 − 8 x − 6 = 0 p x + q + x 2 = 0 p x + q + x^{2} = 0 p x + q + x 2 = 0 where
p = b a p = \frac{b}{a} p = a b p = − 8 p = -8 p = − 8 q = c a q = \frac{c}{a} q = a c q = − 6 q = -6 q = − 6 Vieta Formulas
x 1 + x 2 = − p x_{1} + x_{2} = - p x 1 + x 2 = − p x 1 x 2 = q x_{1} x_{2} = q x 1 x 2 = q x 1 + x 2 = 8 x_{1} + x_{2} = 8 x 1 + x 2 = 8 x 1 x 2 = − 6 x_{1} x_{2} = -6 x 1 x 2 = − 6
The graph
0 5 -15 -10 -5 10 15 20 25 -250 250
Sum and product of roots
[src]
____ ____
0 + 4 - \/ 22 + 4 + \/ 22
( ( 4 − 22 ) + 0 ) + ( 4 + 22 ) \left(\left(4 - \sqrt{22}\right) + 0\right) + \left(4 + \sqrt{22}\right) ( ( 4 − 22 ) + 0 ) + ( 4 + 22 )
/ ____\ / ____\
1*\4 - \/ 22 /*\4 + \/ 22 /
1 ⋅ ( 4 − 22 ) ( 4 + 22 ) 1 \cdot \left(4 - \sqrt{22}\right) \left(4 + \sqrt{22}\right) 1 ⋅ ( 4 − 22 ) ( 4 + 22 )
x 1 = 4 − 22 x_{1} = 4 - \sqrt{22} x 1 = 4 − 22
x 2 = 4 + 22 x_{2} = 4 + \sqrt{22} x 2 = 4 + 22