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How to use it?
- Equation:
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Equation -x^2+4x+3=x^2-x-(1+2x^2)
- Equation x^4-15*x^2-16=0
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Equation x/4+x=4
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Equation x^2+11=0
- Express {x} in terms of y where:
- -11*x-3*y=14
- -1*x-17*y=-12
- 20*x+18*y=-9
- -2*x+20*y=-2
- Graphing y =:
- -x^2+4x+3
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Identical expressions
- -x^ two +4x+ three =x^ two -x-(one + two x^2)
- minus x squared plus 4x plus 3 equally x squared minus x minus (1 plus 2x squared )
- minus x to the power of two plus 4x plus three equally x to the power of two minus x minus (one plus two x squared )
- -x2+4x+3=x2-x-(1+2x2)
- -x2+4x+3=x2-x-1+2x2
- -x²+4x+3=x²-x-(1+2x²)
- -x to the power of 2+4x+3=x to the power of 2-x-(1+2x to the power of 2)
- -x^2+4x+3=x^2-x-1+2x^2
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Similar expressions
- x^2+4x+3=x^2-x-(1+2x^2)
- -x^2+4x+3=x^2+x-(1+2x^2)
- -x^2+4x+3=x^2-x-(1-2x^2)
- -x^2+4x+3=x^2-x+(1+2x^2)
- -x^2+4x-3=x^2-x-(1+2x^2)
- -x^2-4x+3=x^2-x-(1+2x^2)
-x^2+4x+3=x^2-x-(1+2x^2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 2 2 - x + 4*x + 3 = x - x + -1 - 2*x
$$\left(- x^{2} + 4 x\right) + 3 = \left(- 2 x^{2} - 1\right) + \left(x^{2} - x\right)$$
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- x^{2} + 4 x = - x^{2} - x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$- x^{2} + 5 x = - x^{2} + -4$$
Divide both parts of the equation by (-x^2 + 5*x)/x
We get the answer: x = -4/5
-x^2+4*x+3 = x^2-x-(1+2*x^2)
Expand brackets in the right part
-x^2+4*x+3 = x^2-x-1-2*x-2
Looking for similar summands in the right part:
3 - x^2 + 4*x = -1 - x - x^2
Move free summands (without x)
from left part to right part, we given:
$$- x^{2} + 4 x = - x^{2} - x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$- x^{2} + 5 x = - x^{2} + -4$$
Divide both parts of the equation by (-x^2 + 5*x)/x
x = -4 - x^2 / ((-x^2 + 5*x)/x)
We get the answer: x = -4/5
Sum and product of roots
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sum
-4/5
$$- \frac{4}{5}$$
=
-4/5
$$- \frac{4}{5}$$
product
-4/5
$$- \frac{4}{5}$$
=
-4/5
$$- \frac{4}{5}$$
-4/5
The graph