Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x-3(x+3)=-5
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Equation x^2-4x+4=0
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Equation sin(x)=1/5
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Equation x^2+3x+2=0
- Express {x} in terms of y where:
- -17*x+2*y=-4
- -13*x+7*y=-15
- -4*x-8*y=-20
- -9*x+11*y=9
- Graphing y =:
- -2x^2-8x-8
-
Identical expressions
- - two x^2- eight x-8= zero
- minus 2x squared minus 8x minus 8 equally 0
- minus two x squared minus eight x minus 8 equally zero
- -2x2-8x-8=0
- -2x²-8x-8=0
- -2x to the power of 2-8x-8=0
- -2x^2-8x-8=O
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Similar expressions
- -2x^2+8x-8=0
- -2x^2-8x+8=0
- 2x^2-8x-8=0
-2x^2-8x-8=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = -2$$
$$b = -8$$
$$c = -8$$
, then
Because D = 0, then the equation has one root.
$$x_{1} = -2$$
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = -2$$
$$b = -8$$
$$c = -8$$
, then
D = b^2 - 4 * a * c =
(-8)^2 - 4 * (-2) * (-8) = 0
Because D = 0, then the equation has one root.
x = -b/2a = --8/2/(-2)
$$x_{1} = -2$$
Vieta's Theorem
rewrite the equation
$$\left(- 2 x^{2} - 8 x\right) - 8 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} + 4 x + 4 = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 4$$
$$q = \frac{c}{a}$$
$$q = 4$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -4$$
$$x_{1} x_{2} = 4$$
$$\left(- 2 x^{2} - 8 x\right) - 8 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} + 4 x + 4 = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 4$$
$$q = \frac{c}{a}$$
$$q = 4$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -4$$
$$x_{1} x_{2} = 4$$