Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 2*x^2-x-1=x^2-5*x-(-1-x^2)
-
Equation cos(x)=3
-
Equation sin(x)+cos(x)=-1
-
Equation sin(x)-cos(x)=1
- Express {x} in terms of y where:
- 17*x+16*y=7
- 18*x-14*y=-12
- -8*x-15*y=15
- 20*x+5*y=-3
-
Identical expressions
- - two (x- four)= three +7x
- minus 2(x minus 4) equally 3 plus 7x
- minus two (x minus four) equally three plus 7x
- -2x-4=3+7x
-
Similar expressions
- (5x-3)+(7x-4)=8-(15-11x).
- (x-4)^4-2*(x-4)^2-15=0
- -2(x-4)=3-7x
- x^3+7*x^2-20*x-72=0
- -2(x+4)=3+7x
- 2(x-4)=3+7x
- 6x²-2x-4=0
- x^3+7*x^2+14.25*x+9=0
- 1*((x-2)*(x-3)*(x-4)*(x-5))/24+13*((x-1)*(x-3)*(x-4)*(x-5))/(-6)+29*((x-1)*(x-2)*(x-4)*(x-5))/4+49*((x-1)*(x-2)*(x-3)*(x-5))/(-6)+73*((x-1)*(x-2)*(x-3)*(x-4))/24=0
- -2x-4=3x
-2(x-4)=3+7x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 7 x - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-9\right) x = -5$$
Divide both parts of the equation by -9
We get the answer: x = 5/9
-2*(x-4) = 3+7*x
Expand brackets in the left part
-2*x+2*4 = 3+7*x
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 7 x - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-9\right) x = -5$$
Divide both parts of the equation by -9
x = -5 / (-9)
We get the answer: x = 5/9
Sum and product of roots
[src]
sum
5/9
$$\frac{5}{9}$$
=
5/9
$$\frac{5}{9}$$
product
5/9
$$\frac{5}{9}$$
=
5/9
$$\frac{5}{9}$$
5/9
The graph