Mister Exam
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- Equation:
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Equation x^2+x-4=0
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Equation x^4=(4x-21)^2
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Equation -2(x-4)=3+7x
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Equation cos(pi*(x-1)/3)=1/2
- Express {x} in terms of y where:
- -2*x-14*y=7
- 14*x+16*y=-3
- -17*x+13*y=-3
- 7*x+20*y=-17
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Identical expressions
- - two (x- four)= three +7x
- minus 2(x minus 4) equally 3 plus 7x
- minus two (x minus four) equally three plus 7x
- -2x-4=3+7x
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Similar expressions
- (5x-3)+(7x-4)=8-(15-11x).
- (x-4)^4-2*(x-4)^2-15=0
- -2(x-4)=3-7x
- x^3+7*x^2-20*x-72=0
- -2(x+4)=3+7x
- 2(x-4)=3+7x
- 6x²-2x-4=0
- x^3+7*x^2+14.25*x+9=0
- 1*((x-2)*(x-3)*(x-4)*(x-5))/24+13*((x-1)*(x-3)*(x-4)*(x-5))/(-6)+29*((x-1)*(x-2)*(x-4)*(x-5))/4+49*((x-1)*(x-2)*(x-3)*(x-5))/(-6)+73*((x-1)*(x-2)*(x-3)*(x-4))/24=0
- -2x-4=3x
-2(x-4)=3+7x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 7 x - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-9\right) x = -5$$
Divide both parts of the equation by -9
We get the answer: x = 5/9
-2*(x-4) = 3+7*x
Expand brackets in the left part
-2*x+2*4 = 3+7*x
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 7 x - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-9\right) x = -5$$
Divide both parts of the equation by -9
x = -5 / (-9)
We get the answer: x = 5/9
Sum and product of roots
[src]
sum
5/9
$$\frac{5}{9}$$
=
5/9
$$\frac{5}{9}$$
product
5/9
$$\frac{5}{9}$$
=
5/9
$$\frac{5}{9}$$
5/9
The graph