-(26/5)+x=-(5/2) equation
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The solution
Detail solution
Given the linear equation:
-(26/5)+x = -(5/2)
Expand brackets in the left part
-26/5+x = -(5/2)
Expand brackets in the right part
-26/5+x = -5/2
Move free summands (without x)
from left part to right part, we given:
$$x = \frac{27}{10}$$
We get the answer: x = 27/10
$$x_{1} = \frac{27}{10}$$
Sum and product of roots
[src]
$$0 + \frac{27}{10}$$
$$\frac{27}{10}$$
$$1 \cdot \frac{27}{10}$$
$$\frac{27}{10}$$