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Identical expressions
- - three (3x+ four)+ four (2x- one)= zero
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Similar expressions
- -3(3x-4)+4(2x-1)=0
- 3(3x+4)+4(2x-1)=0
- -3(3x+4)-4(2x-1)=0
- -3(3x+4)+4(2x+1)=0
-3(3x+4)+4(2x-1)=0 equation
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The solution
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-3*(3*x + 4) + 4*(2*x - 1) = 0
$$4 \left(2 x - 1\right) - 3 \left(3 x + 4\right) = 0$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- x = 16$$
Divide both parts of the equation by -1
We get the answer: x = -16
-3*(3*x+4)+4*(2*x-1) = 0
Expand brackets in the left part
-3*3*x-3*4+4*2*x-4*1 = 0
Looking for similar summands in the left part:
-16 - x = 0
Move free summands (without x)
from left part to right part, we given:
$$- x = 16$$
Divide both parts of the equation by -1
x = 16 / (-1)
We get the answer: x = -16