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-(4-y)+2y+1=0

-(4-y)+2y+1=0 equation

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Numerical solution:

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The solution

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-4 + y + 2*y + 1 = 0
$$\left(2 y + \left(y - 4\right)\right) + 1 = 0$$
Detail solution
Given the linear equation:
-(4-y)+2*y+1 = 0

Expand brackets in the left part
-4+y+2*y+1 = 0

Looking for similar summands in the left part:
-3 + 3*y = 0

Move free summands (without y)
from left part to right part, we given:
$$3 y = 3$$
Divide both parts of the equation by 3
y = 3 / (3)

We get the answer: y = 1
The graph
Rapid solution [src]
y1 = 1
$$y_{1} = 1$$
y1 = 1
Sum and product of roots [src]
sum
1
$$1$$
=
1
$$1$$
product
1
$$1$$
=
1
$$1$$
1
Numerical answer [src]
y1 = 1.0
y1 = 1.0
The graph
-(4-y)+2y+1=0 equation