Mister Exam
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How to use it?
- Equation:
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Equation x^3+5*x^2-4*x-20=0
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Equation 3*x+50=70
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Equation 9^x+2*3^x-3=0
- Express {x} in terms of y where:
- -20*x-13*y=9
- 6*x+8*y=0
- 17*x-3*y=-10
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Identical expressions
- -(3y+ seven)= eight - two (eight -y)
- minus (3y plus 7) equally 8 minus 2(8 minus y)
- minus (3y plus seven) equally eight minus two (eight minus y)
- -3y+7=8-28-y
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Similar expressions
- -(3y-7)=8-2(8-y)
- -(3y+7)=8+2(8-y)
- 8(3y-2)-13y=5(12-3y)+7y
- (y-3)(y+7)=0
- -(3y+7)=8-2(8+y)
- (3y+7)=8-2(8-y)
- y-(3(y+7)/x)*0=x/2
-(3y+7)=8-2(8-y) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without y)
from left part to right part, we given:
$$- 3 y = 2 y - 1$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-5\right) y = -1$$
Divide both parts of the equation by -5
We get the answer: y = 1/5
-(3*y+7) = 8-2*(8-y)
Expand brackets in the left part
-3*y-7 = 8-2*(8-y)
Expand brackets in the right part
-3*y-7 = 8-2*8+2*y
Looking for similar summands in the right part:
-7 - 3*y = -8 + 2*y
Move free summands (without y)
from left part to right part, we given:
$$- 3 y = 2 y - 1$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-5\right) y = -1$$
Divide both parts of the equation by -5
y = -1 / (-5)
We get the answer: y = 1/5
Sum and product of roots
[src]
sum
1/5
$$\frac{1}{5}$$
=
1/5
$$\frac{1}{5}$$
product
1/5
$$\frac{1}{5}$$
=
1/5
$$\frac{1}{5}$$
1/5
The graph