Mister Exam
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How to use it?
- Equation:
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Equation 15-x=8
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Equation (x+1)^2=0
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Equation x^2+3*x+9=0
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Equation -2x=7-3(3x-7)
- Express {x} in terms of y where:
- 4*x+7*y=1
- -7*x+15*y=7
- -10*x-11*y=10
- -7*x-9*y=-11
- Derivative of:
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-2x
- Integral of d{x}:
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-2x
- Graphing y =:
- -2x
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Identical expressions
- -2x= seven - three (3x- seven)
- minus 2x equally 7 minus 3(3x minus 7)
- minus 2x equally seven minus three (3x minus seven)
- -2x=7-33x-7
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Similar expressions
- 2x=7-3(3x-7)
- -2x=7+3(3x-7)
- -2x=7-3(3x+7)
- x^3-2*x^2+x+3=0
- x^2-2*x-8=0
-2x=7-3(3x-7) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move the summands with the unknown x
from the right part to the left part:
$$7 x = 28$$
Divide both parts of the equation by 7
We get the answer: x = 4
-2*x = 7-3*(3*x-7)
Expand brackets in the right part
-2*x = 7-3*3*x+3*7
Looking for similar summands in the right part:
-2*x = 28 - 9*x
Move the summands with the unknown x
from the right part to the left part:
$$7 x = 28$$
Divide both parts of the equation by 7
x = 28 / (7)
We get the answer: x = 4
The graph