log(x)=x-5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
$$x_{1} = - W\left(- \frac{1}{e^{5}}\right)$$
$$x_{2} = - W_{-1}\left(- \frac{1}{e^{5}}\right)$$
x2 = -LambertW(-exp(-5, -1))
Sum and product of roots
[src]
/ -5\ / -5 \
- W\-e / - W\-e , -1/
$$- W\left(- \frac{1}{e^{5}}\right) - W_{-1}\left(- \frac{1}{e^{5}}\right)$$
/ -5\ / -5 \
- W\-e / - W\-e , -1/
$$- W\left(- \frac{1}{e^{5}}\right) - W_{-1}\left(- \frac{1}{e^{5}}\right)$$
/ -5\ / / -5 \\
-W\-e /*\-W\-e , -1//
$$- W\left(- \frac{1}{e^{5}}\right) \left(- W_{-1}\left(- \frac{1}{e^{5}}\right)\right)$$
/ -5\ / -5 \
W\-e /*W\-e , -1/
$$W\left(- \frac{1}{e^{5}}\right) W_{-1}\left(- \frac{1}{e^{5}}\right)$$
LambertW(-exp(-5))*LambertW(-exp(-5), -1)