log2(x^2+3x)=2 equation
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The solution
Detail solution
Given the equation
log(2)log(x2+3x)=2transform
log(2)log(4x(x+3))=0log(2)log(x2+3x)−2=0Do replacement
w=log(x2+3x)Expand brackets in the left part
-2 + w/log2 = 0
Move free summands (without w)
from left part to right part, we given:
log(2)w=2Divide both parts of the equation by 1/log(2)
w = 2 / (1/log(2))
We get the answer: w = log(4)
do backward replacement
log(x2+3x)=wsubstitute w:
Sum and product of roots
[src]
(−4+0)+1
1(−4)1