Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 25*x^3-10*x^2+x=0
-
Equation 2x^2-x-1=x^2-5x-(-1-x^2)
-
Equation 2^x=5
-
Equation (x-10)^2=(x+4)^2
- Express {x} in terms of y where:
- 15*x+12*y=-19
- -19*x-20*y=-4
- -18*x+12*y=-8
- -14*x+4*y=-16
-
Identical expressions
- log two (x- seventeen)=2
- logarithm of 2(x minus 17) equally 2
- logarithm of two (x minus seventeen) equally 2
- log2x-17=2
-
Similar expressions
- log2(x+17)=2
- log(x^2-1)/log(2)=log(2*x-17)/log(2)
log2(x-17)=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
log(x - 17) ----------- = 2 log(2)
$$\frac{\log{\left(x - 17 \right)}}{\log{\left(2 \right)}} = 2$$
Detail solution
Given the equation
$$\frac{\log{\left(x - 17 \right)}}{\log{\left(2 \right)}} = 2$$
$$\frac{\log{\left(x - 17 \right)}}{\log{\left(2 \right)}} = 2$$
Let's divide both parts of the equation by the multiplier of log =1/log(2)
$$\log{\left(x - 17 \right)} = 2 \log{\left(2 \right)}$$
This equation is of the form:
By definition log
then
$$x - 17 = e^{\frac{2}{\frac{1}{\log{\left(2 \right)}}}}$$
simplify
$$x - 17 = 4$$
$$x = 21$$
$$\frac{\log{\left(x - 17 \right)}}{\log{\left(2 \right)}} = 2$$
$$\frac{\log{\left(x - 17 \right)}}{\log{\left(2 \right)}} = 2$$
Let's divide both parts of the equation by the multiplier of log =1/log(2)
$$\log{\left(x - 17 \right)} = 2 \log{\left(2 \right)}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$x - 17 = e^{\frac{2}{\frac{1}{\log{\left(2 \right)}}}}$$
simplify
$$x - 17 = 4$$
$$x = 21$$