Mister Exam
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How to use it?
- Equation:
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Equation x^2/(x+6)=1/2
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Equation 80-x=9*5
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Equation 3x-2(3x-2)=19
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Equation 8-3/5x=14
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Identical expressions
- log_5(2x- seven)= three
- logarithm of _5(2x minus 7) equally 3
- logarithm of _5(2x minus seven) equally three
- log_52x-7=3
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Similar expressions
- log_5(2x+7)=3
log_5(2x-7)=3 equation
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The solution
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log(2*x - 7) ------------ = 3 log(5)
$$\frac{\log{\left(2 x - 7 \right)}}{\log{\left(5 \right)}} = 3$$
Detail solution
Given the equation
$$\frac{\log{\left(2 x - 7 \right)}}{\log{\left(5 \right)}} = 3$$
$$\frac{\log{\left(2 x - 7 \right)}}{\log{\left(5 \right)}} = 3$$
Let's divide both parts of the equation by the multiplier of log =1/log(5)
$$\log{\left(2 x - 7 \right)} = 3 \log{\left(5 \right)}$$
This equation is of the form:
By definition log
then
$$2 x - 7 = e^{\frac{3}{\frac{1}{\log{\left(5 \right)}}}}$$
simplify
$$2 x - 7 = 125$$
$$2 x = 132$$
$$x = 66$$
$$\frac{\log{\left(2 x - 7 \right)}}{\log{\left(5 \right)}} = 3$$
$$\frac{\log{\left(2 x - 7 \right)}}{\log{\left(5 \right)}} = 3$$
Let's divide both parts of the equation by the multiplier of log =1/log(5)
$$\log{\left(2 x - 7 \right)} = 3 \log{\left(5 \right)}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$2 x - 7 = e^{\frac{3}{\frac{1}{\log{\left(5 \right)}}}}$$
simplify
$$2 x - 7 = 125$$
$$2 x = 132$$
$$x = 66$$