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Similar expressions
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log3(7-x)=2 equation
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The solution
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log(7 - x) ---------- = 2 log(3)
$$\frac{\log{\left(7 - x \right)}}{\log{\left(3 \right)}} = 2$$
Detail solution
Given the equation
$$\frac{\log{\left(7 - x \right)}}{\log{\left(3 \right)}} = 2$$
$$\frac{\log{\left(7 - x \right)}}{\log{\left(3 \right)}} = 2$$
Let's divide both parts of the equation by the multiplier of log =1/log(3)
$$\log{\left(7 - x \right)} = 2 \log{\left(3 \right)}$$
This equation is of the form:
By definition log
then
$$7 - x = e^{\frac{2}{\frac{1}{\log{\left(3 \right)}}}}$$
simplify
$$7 - x = 9$$
$$- x = 2$$
$$x = -2$$
$$\frac{\log{\left(7 - x \right)}}{\log{\left(3 \right)}} = 2$$
$$\frac{\log{\left(7 - x \right)}}{\log{\left(3 \right)}} = 2$$
Let's divide both parts of the equation by the multiplier of log =1/log(3)
$$\log{\left(7 - x \right)} = 2 \log{\left(3 \right)}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$7 - x = e^{\frac{2}{\frac{1}{\log{\left(3 \right)}}}}$$
simplify
$$7 - x = 9$$
$$- x = 2$$
$$x = -2$$