The teacher will be very surprised to see your correct solution 😉
3^log(3)^7-x = 5
3^log3^7-x = 5
x = 5 / ((3^(log(3)^7) - x)/x)
7
log (3)
x1 = -5 + 3
x1 = -5 + 3^(log(3)^7)
sum
7
log (3)
-5 + 3
=
7
log (3)
-5 + 3
product
7
log (3)
-5 + 3
=
7
log (3)
-5 + 3
-5 + 3^(log(3)^7)