lg²x+2lgx=8 equation

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You have entered [src]

   2                  
log (x) + 2*log(x) = 8

$$\log{\left(x \right)}^{2} + 2 \log{\left(x \right)} = 8$$

Simplify

The graph

Plot the graph f1(x)

Plot the graph f2(x)

Rapid solution [src]

      -4
x1 = e

$$x_{1} = e^{-4}$$

      2
x2 = e

$$x_{2} = e^{2}$$

x2 = exp(2)

Sum and product of roots [src]

sum

 -4    2
e   + e

$$e^{-4} + e^{2}$$

 -4    2
e   + e

$$e^{-4} + e^{2}$$

product

 -4  2
e  *e

$$\frac{e^{2}}{e^{4}}$$

 -2
e

$$e^{-2}$$

exp(-2)

Numerical answer [src]

x1 = 7.38905609893065

x2 = 7.38905609893065 - 9.08134065356179e-17*i

x2 = 7.38905609893065 - 9.08134065356179e-17*i