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k^2-2*k+1=0

k^2-2*k+1=0 equation

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Numerical solution:

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The solution

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 2              
k  - 2*k + 1 = 0
(k2−2k)+1=0\left(k^{2} - 2 k\right) + 1 = 0
Simplify
Detail solution
This equation is of the form
a*k^2 + b*k + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
k1=D−b2ak_{1} = \frac{\sqrt{D} - b}{2 a}
k2=−D−b2ak_{2} = \frac{- \sqrt{D} - b}{2 a}
where D = b^2 - 4*a*c - it is the discriminant.
Because
a=1a = 1
b=−2b = -2
c=1c = 1
, then
D = b^2 - 4 * a * c = 

(-2)^2 - 4 * (1) * (1) = 0

Because D = 0, then the equation has one root.
k = -b/2a = --2/2/(1)

k1=1k_{1} = 1
Vieta's Theorem
it is reduced quadratic equation
k2+kp+q=0k^{2} + k p + q = 0
where
p=bap = \frac{b}{a}
p=−2p = -2
q=caq = \frac{c}{a}
q=1q = 1
Vieta Formulas
k1+k2=−pk_{1} + k_{2} = - p
k1k2=qk_{1} k_{2} = q
k1+k2=2k_{1} + k_{2} = 2
k1k2=1k_{1} k_{2} = 1
The graph
-12.5-10.0-7.5-5.0-2.50.02.55.07.510.012.515.00200
Plot the graph f1(x)
Plot the graph f2(x)
Sum and product of roots [src] 
sum
1
11 
=
1
11 
product
1
11 
=
1
11 
1
Rapid solution [src] 
k1 = 1
k1=1k_{1} = 1 
k1 = 1
Numerical answer [src] 
k1 = 1.0
k1 = 1.0
The graph
k^2-2*k+1=0 equation
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