Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation 3x^2-75=0
- Equation (49^sinx)^cosx=7^(sqrt3)^sinx
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Equation (K+11)/23=27
-
Equation 9x^2=27x
- Express {x} in terms of y where:
- 15*x-17*y=19
- 9*x-8*y=6
- 15*x+15*y=16
- -4*x+18*y=-14
- Sum of series:
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27
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Identical expressions
- (K+ eleven)/ twenty-three = twenty-seven
- (K plus 11) divide by 23 equally 27
- (K plus eleven) divide by twenty minus three equally twenty minus seven
- K+11/23=27
- (K+11) divide by 23=27
-
Similar expressions
- (K-11)/23=27
(K+11)/23=27 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without k)
from left part to right part, we given:
$$\frac{k}{23} = \frac{610}{23}$$
Divide both parts of the equation by 1/23
We get the answer: k = 610
(k+11)/23 = 27
Expand brackets in the left part
k/23+11/23 = 27
Move free summands (without k)
from left part to right part, we given:
$$\frac{k}{23} = \frac{610}{23}$$
Divide both parts of the equation by 1/23
k = 610/23 / (1/23)
We get the answer: k = 610
Sum and product of roots
[src]
sum
0 + 610
$$0 + 610$$
=
610
$$610$$
product
1*610
$$1 \cdot 610$$
=
610
$$610$$
610
The graph