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isinz+cosz=i equation

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Numerical solution:

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I*sin(z) + cos(z) = I
$$i \sin{\left(z \right)} + \cos{\left(z \right)} = i$$
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Numerical answer [src]
z1 = 70.6858347057703
z2 = -4.71238898038469
z3 = -48.6946861306418
z4 = -36.1283155162826
z5 = 83.2522053201295
z6 = -92.6769832808989
z7 = -61.261056745001
z8 = -17.2787595947439
z9 = -67.5442420521806
z10 = 32.9867228626928
z11 = 20.4203522483337
z12 = 95.8185759344887
z13 = 45.553093477052
z14 = -54.9778714378214
z15 = -29.845130209103
z16 = -73.8274273593601
z17 = 1.5707963267949
z18 = 14.1371669411541
z19 = 58.1194640914112
z20 = -10.9955742875643
z21 = 39.2699081698724
z22 = -23.5619449019235
z23 = 89.5353906273091
z24 = 76.9690200129499
z25 = 64.4026493985908
z26 = -86.3937979737193
z27 = 7.85398163397448
z28 = 26.7035375555132
z29 = -80.1106126665397
z30 = -42.4115008234622
z31 = 102.101761241668
z32 = -98.9601685880785
z33 = 51.8362787842316
z33 = 51.8362787842316