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4^(x-1)=1

4^(x-1)=1 equation

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Numerical solution:

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The solution

You have entered [src]
 x - 1    
4      = 1
$$4^{x - 1} = 1$$
Detail solution
Given the equation:
$$4^{x - 1} = 1$$
or
$$4^{x - 1} - 1 = 0$$
or
$$\frac{4^{x}}{4} = 1$$
or
$$4^{x} = 4$$
- this is the simplest exponential equation
Do replacement
$$v = 4^{x}$$
we get
$$v - 4 = 0$$
or
$$v - 4 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 4$$
We get the answer: v = 4
do backward replacement
$$4^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(4 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(4 \right)}}{\log{\left(4 \right)}} = 1$$
The graph
Rapid solution [src]
x1 = 1
$$x_{1} = 1$$
          pi*I 
x2 = 1 + ------
         log(2)
$$x_{2} = 1 + \frac{i \pi}{\log{\left(2 \right)}}$$
x2 = 1 + i*pi/log(2)
Sum and product of roots [src]
sum
         pi*I 
1 + 1 + ------
        log(2)
$$1 + \left(1 + \frac{i \pi}{\log{\left(2 \right)}}\right)$$
=
     pi*I 
2 + ------
    log(2)
$$2 + \frac{i \pi}{\log{\left(2 \right)}}$$
product
     pi*I 
1 + ------
    log(2)
$$1 + \frac{i \pi}{\log{\left(2 \right)}}$$
=
     pi*I 
1 + ------
    log(2)
$$1 + \frac{i \pi}{\log{\left(2 \right)}}$$
1 + pi*i/log(2)
Numerical answer [src]
x1 = 1.0
x2 = 1.0 + 4.53236014182719*i
x2 = 1.0 + 4.53236014182719*i
The graph
4^(x-1)=1 equation