4*x+2*y=8 equation
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The solution
Detail solution
Given the linear equation:
4*x+2*y = 8
Looking for similar summands in the left part:
2*y + 4*x = 8
Move the summands with the other variables
from left part to right part, we given:
$$4 x = 8 - 2 y$$
Divide both parts of the equation by 4
x = 8 - 2*y / (4)
We get the answer: x = 2 - y/2
re(y) I*im(y)
x1 = 2 - ----- - -------
2 2
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$
x1 = -re(y)/2 - i*im(y)/2 + 2
Sum and product of roots
[src]
re(y) I*im(y)
2 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$
re(y) I*im(y)
2 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$
re(y) I*im(y)
2 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$
re(y) I*im(y)
2 - ----- - -------
2 2
$$- \frac{\operatorname{re}{\left(y\right)}}{2} - \frac{i \operatorname{im}{\left(y\right)}}{2} + 2$$