4(x+2y)-8=5x-2 equation
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The solution
Detail solution
Given the linear equation:
4*(x+2*y)-8 = 5*x-2
Expand brackets in the left part
4*x+4*2*y-8 = 5*x-2
Looking for similar summands in the left part:
-8 + 4*x + 8*y = 5*x-2
Move free summands (without x)
from left part to right part, we given:
$$4 x + 8 y = 5 x + 6$$
Move the summands with the other variables
from left part to right part, we given:
$$4 x = 5 x + \left(-8\right) y + 6$$
Divide both parts of the equation by 4
x = 6 - 8*y + 5*x / (4)
We get the answer: x = -6 + 8*y
x1 = -6 + 8*re(y) + 8*I*im(y)
$$x_{1} = 8 \operatorname{re}{\left(y\right)} + 8 i \operatorname{im}{\left(y\right)} - 6$$
x1 = 8*re(y) + 8*i*im(y) - 6
Sum and product of roots
[src]
$$8 \operatorname{re}{\left(y\right)} + 8 i \operatorname{im}{\left(y\right)} - 6$$
$$8 \operatorname{re}{\left(y\right)} + 8 i \operatorname{im}{\left(y\right)} - 6$$
$$8 \operatorname{re}{\left(y\right)} + 8 i \operatorname{im}{\left(y\right)} - 6$$
$$8 \operatorname{re}{\left(y\right)} + 8 i \operatorname{im}{\left(y\right)} - 6$$