Mister Exam
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How to use it?
- Equation:
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Equation x^3=3
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Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
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Equation x^2+6=5x
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- -19*x-15*y=15
- 13*x-11*y=16
- Derivative of:
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4*x+5
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Identical expressions
- four *x+ five = two *x- seven
- 4 multiply by x plus 5 equally 2 multiply by x minus 7
- four multiply by x plus five equally two multiply by x minus seven
- 4x+5=2x-7
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Similar expressions
- 4x+5(3-2x)=5-11x
- sqrt4(4x+5-x^2)-sqrt(4x-x^2-3)=1
- 4x^2+4x+5=0
- 4*x+5=2*x+7
- (x+3)/4=(2x-7)/5
- 4*x-5=2*x-7
- (x^2-5x+7)^2-(x+2)(x-7)=27
4*x+5=2*x-7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$4 x = 2 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x = -12$$
Divide both parts of the equation by 2
We get the answer: x = -6
4*x+5 = 2*x-7
Move free summands (without x)
from left part to right part, we given:
$$4 x = 2 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x = -12$$
Divide both parts of the equation by 2
x = -12 / (2)
We get the answer: x = -6
The graph