4-2(x+3)=4(x-5) equation
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The solution
Detail solution
Given the linear equation:
4-2*(x+3) = 4*(x-5)
Expand brackets in the left part
4-2*x-2*3 = 4*(x-5)
Expand brackets in the right part
4-2*x-2*3 = 4*x-4*5
Looking for similar summands in the left part:
-2 - 2*x = 4*x-4*5
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 4 x - 18$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-6\right) x = -18$$
Divide both parts of the equation by -6
x = -18 / (-6)
We get the answer: x = 3
Sum and product of roots
[src]
$$3$$
$$3$$
$$3$$
$$3$$