5|4x-8|+7,6=22 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$4 x - 8 \geq 0$$
or
$$2 \leq x \wedge x < \infty$$
we get the equation
$$5 \left(4 x - 8\right) - \frac{72}{5} = 0$$
after simplifying we get
$$20 x - \frac{272}{5} = 0$$
the solution in this interval:
$$x_{1} = \frac{68}{25}$$
2.
$$4 x - 8 < 0$$
or
$$-\infty < x \wedge x < 2$$
we get the equation
$$5 \left(8 - 4 x\right) - \frac{72}{5} = 0$$
after simplifying we get
$$\frac{128}{5} - 20 x = 0$$
the solution in this interval:
$$x_{2} = \frac{32}{25}$$
The final answer:
$$x_{1} = \frac{68}{25}$$
$$x_{2} = \frac{32}{25}$$
$$x_{1} = \frac{32}{25}$$
$$x_{2} = \frac{68}{25}$$
Sum and product of roots
[src]
$$\frac{32}{25} + \frac{68}{25}$$
$$4$$
$$\frac{32 \cdot 68}{25 \cdot 25}$$
$$\frac{2176}{625}$$