Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x^2-x=0
-
Equation 3x=8
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Equation 4*x-8=x+1
-
Equation 4*x^2-13*x+3=0
- Express {x} in terms of y where:
- 2*x+12*y=11
- -14*x+12*y=-18
- 1*x+18*y=16
- 20*x+7*y=-16
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Identical expressions
- two (two -y)=y- five
- 2(2 minus y) equally y minus 5
- two (two minus y) equally y minus five
- 22-y=y-5
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Similar expressions
- (y^2-6)(y^2+2)=(y^2-2)^2-y
- 9*(4+y)-5*y=5*y-66
- 2(2+y)=y-5
- (2-3*y)*(2+3*y)=(9*y-2)*(2-y)
- 2(2-y)=y+5
- (3/2)*(8*x-6*y)-(5*y-3*x)*(12/5)=0
2(2-y)=y-5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without y)
from left part to right part, we given:
$$- 2 y = y - 9$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-3\right) y = -9$$
Divide both parts of the equation by -3
We get the answer: y = 3
2*(2-y) = y-5
Expand brackets in the left part
2*2-2*y = y-5
Move free summands (without y)
from left part to right part, we given:
$$- 2 y = y - 9$$
Move the summands with the unknown y
from the right part to the left part:
$$\left(-3\right) y = -9$$
Divide both parts of the equation by -3
y = -9 / (-3)
We get the answer: y = 3
The graph