Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x-4)^2-x^2=0
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Equation -x^2+4x+3=x^2-x-(1+2x^2)
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Equation (x-1)^3=-8
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Equation 5x+12=8x+30
- Express {x} in terms of y where:
- 10*x-15*y=16
- -6*x+12*y=11
- -18*x-6*y=-1
- 20*x+18*y=-9
- Integral of d{x}:
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4*x
- Derivative of:
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4*x
- 4*x
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Identical expressions
- five - two *(x- one)= four *x
- 5 minus 2 multiply by (x minus 1) equally 4 multiply by x
- five minus two multiply by (x minus one) equally four multiply by x
- 5-2(x-1)=4x
- 5-2x-1=4x
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Similar expressions
- 5+2*(x-1)=4*x
- (sqrt(5)+2)^(x-1)=(sqrt(5)-2)^((x-1)/(x+1))
- 5-2*(x+1)=4*x
- (x-6)(4x-6)=0
- (5-2(x-1))=4-x
- -x^2+4x+3=x^2-x-(1+2x^2)
- 15^8x-9=(1/15)^-2x-1
- 3x+5=-4x+19
- (x-6)^2=-24x
- x^4=(4x-5)^2
5-2*(x-1)=4*x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by -6
We get the answer: x = 7/6
5-2*(x-1) = 4*x
Expand brackets in the left part
5-2*x+2*1 = 4*x
Looking for similar summands in the left part:
7 - 2*x = 4*x
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by -6
x = -7 / (-6)
We get the answer: x = 7/6