5/(20-6x)=1/10 equation
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The solution
Detail solution
Given the equation:
$$\frac{5}{20 - 6 x} = \frac{1}{10}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 5
b1 = 20 - 6*x
a2 = 1
b2 = 10
so we get the equation
$$5 \cdot 10 = 20 - 6 x$$
$$50 = 20 - 6 x$$
Move free summands (without x)
from left part to right part, we given:
$$0 = - 6 x - 30$$
Move the summands with the unknown x
from the right part to the left part:
$$6 x = -30$$
Divide both parts of the equation by 6
x = -30 / (6)
We get the answer: x = -5
Sum and product of roots
[src]
$$-5$$
$$-5$$
$$-5$$
$$-5$$