Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2*x^2-x-1=x^2-5*x-(-1-x^2)
-
Equation cos(x)=3
-
Equation sin(x)+cos(x)=-1
-
Equation sin(x)-cos(x)=1
- Express {x} in terms of y where:
- 17*x+16*y=7
- 18*x-14*y=-12
- -8*x-15*y=15
- 20*x+5*y=-3
-
Identical expressions
- five (7x+ three)- twelve = four (9x- six)
- 5(7x plus 3) minus 12 equally 4(9x minus 6)
- five (7x plus three) minus twelve equally four (9x minus six)
- 57x+3-12=49x-6
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Similar expressions
- 5(7x+3)+12=4(9x-6)
- 5(7x+3)-12=4(9x+6)
- x^2-(126/49)*x-61/49=0
- 5(7x-3)-12=4(9x-6)
5(7x+3)-12=4(9x-6) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
5*(7*x + 3) - 12 = 4*(9*x - 6)
$$5 \cdot \left(7 x + 3\right) - 12 = 4 \cdot \left(9 x - 6\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$35 x = 36 x - 27$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = -27$$
Divide both parts of the equation by -1
We get the answer: x = 27
5*(7*x+3)-12 = 4*(9*x-6)
Expand brackets in the left part
5*7*x+5*3-12 = 4*(9*x-6)
Expand brackets in the right part
5*7*x+5*3-12 = 4*9*x-4*6
Looking for similar summands in the left part:
3 + 35*x = 4*9*x-4*6
Move free summands (without x)
from left part to right part, we given:
$$35 x = 36 x - 27$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = -27$$
Divide both parts of the equation by -1
x = -27 / (-1)
We get the answer: x = 27
Sum and product of roots
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sum
27
$$\left(27\right)$$
=
27
$$27$$
product
27
$$\left(27\right)$$
=
27
$$27$$
The graph