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- Equation:
- Equation 64-x^2=0
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Equation 2*x^2+7*x-4=0
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Equation 11/(x+4)=-11/7
-
Equation x^6=(x-5)^3
- Express {x} in terms of y where:
- 10*x-6*y=10
- 20*x+6*y=7
- 17*x-7*y=7
- 3*x+9*y=7
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Identical expressions
- eleven /(x+ four)=- eleven / seven
- 11 divide by (x plus 4) equally minus 11 divide by 7
- eleven divide by (x plus four) equally minus eleven divide by seven
- 11/x+4=-11/7
- 11 divide by (x+4)=-11 divide by 7
-
Similar expressions
- 11/x+4=-11/7
- 11/(x-4)=-11/7
- 11/(x+4)=+11/7
- 4*(a+5/12)=1*(1)/(6)*(6*a-1*(1)/(7))
- 7*x+1/x+4-(x-11)/x+4=0
11/(x+4)=-11/7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{11}{x + 4} = - \frac{11}{7}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{\left(-7\right) 11}{11} = x + 4$$
$$-7 = x + 4$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 11$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 11$$
Divide both parts of the equation by -1
We get the answer: x = -11
$$\frac{11}{x + 4} = - \frac{11}{7}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 11
b1 = 4 + x
a2 = 1
b2 = -7/11
so we get the equation
$$\frac{\left(-7\right) 11}{11} = x + 4$$
$$-7 = x + 4$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 11$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 11$$
Divide both parts of the equation by -1
x = 11 / (-1)
We get the answer: x = -11
The graph