Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3*x^2-8*x-3=0
-
Equation x^3=9
- Equation 4/3*x^2-48=0
-
Equation z^4+z^2+1=0
- Express {x} in terms of y where:
- -10*x+5*y=10
- -18*x+16*y=4
- 6*x+9*y=15
- -8*x-15*y=-12
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Identical expressions
- eight - five (2x- three)= twelve -6x
- 8 minus 5(2x minus 3) equally 12 minus 6x
- eight minus five (2x minus three) equally twelve minus 6x
- 8-52x-3=12-6x
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Similar expressions
- -11x1^2-6x2^2-6x3^2+12x1x2-102x1x3+6x2x3
- 8-5(2x-3)=12+6x
- 8+5(2x-3)=12-6x
- 8-5(2x+3)=12-6x
8-5(2x-3)=12-6x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 10 x = - 6 x - 11$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-4\right) x = -11$$
Divide both parts of the equation by -4
We get the answer: x = 11/4
8-5*(2*x-3) = 12-6*x
Expand brackets in the left part
8-5*2*x+5*3 = 12-6*x
Looking for similar summands in the left part:
23 - 10*x = 12-6*x
Move free summands (without x)
from left part to right part, we given:
$$- 10 x = - 6 x - 11$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-4\right) x = -11$$
Divide both parts of the equation by -4
x = -11 / (-4)
We get the answer: x = 11/4
Sum and product of roots
[src]
sum
11/4
$$\frac{11}{4}$$
=
11/4
$$\frac{11}{4}$$
product
11/4
$$\frac{11}{4}$$
=
11/4
$$\frac{11}{4}$$
11/4