e^x+1=0 equation
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The solution
Detail solution
Given the equation:
$$e^{x} + 1 = 0$$
or
$$e^{x} + 1 = 0$$
or
$$e^{x} = -1$$
or
$$e^{x} = -1$$
- this is the simplest exponential equation
Do replacement
$$v = e^{x}$$
we get
$$v + 1 = 0$$
or
$$v + 1 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = -1$$
We get the answer: v = -1
do backward replacement
$$e^{x} = v$$
or
$$x = \log{\left(v \right)}$$
The final answer
$$x_{1} = \frac{\log{\left(-1 \right)}}{\log{\left(e \right)}} = i \pi$$
Sum and product of roots
[src]
$$i \pi$$
$$i \pi$$
$$i \pi$$
$$i \pi$$