Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2*x^2-x+5=0
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Equation e^x=1
-
Equation x^2+2=x+2
-
Equation 5=12-5(4x-1)
- Express {x} in terms of y where:
- -12*x-2*y=-15
- -4*x+4*y=-9
- -19*x-2*y=-6
- -2*x+2*y=4
- Derivative of:
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e^x
- Integral of d{x}:
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e^x
- Graphing y =:
- e^x
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Identical expressions
- e^x= one
- e to the power of x equally 1
- e to the power of x equally one
- ex=1
e^x=1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$e^{x} = 1$$
or
$$e^{x} - 1 = 0$$
or
$$e^{x} = 1$$
or
$$e^{x} = 1$$
- this is the simplest exponential equation
Do replacement
$$v = e^{x}$$
we get
$$v - 1 = 0$$
or
$$v - 1 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 1$$
We get the answer: v = 1
do backward replacement
$$e^{x} = v$$
or
$$x = \log{\left(v \right)}$$
The final answer
$$x_{1} = \frac{\log{\left(1 \right)}}{\log{\left(e \right)}} = 0$$
$$e^{x} = 1$$
or
$$e^{x} - 1 = 0$$
or
$$e^{x} = 1$$
or
$$e^{x} = 1$$
- this is the simplest exponential equation
Do replacement
$$v = e^{x}$$
we get
$$v - 1 = 0$$
or
$$v - 1 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 1$$
We get the answer: v = 1
do backward replacement
$$e^{x} = v$$
or
$$x = \log{\left(v \right)}$$
The final answer
$$x_{1} = \frac{\log{\left(1 \right)}}{\log{\left(e \right)}} = 0$$
The graph