Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x+9=13-x
-
Equation x^2+4x+13=0
-
Equation log(x)-3+1/x=0
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Equation x+6(3-3x)=35
- Express {x} in terms of y where:
- 2*x+13*y=-7
- -4*x-1*y=-6
- -7*x-1*y=7
- -20*x+17*y=-16
- Derivative of:
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ctg(x)
- Integral of d{x}:
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ctg(x)
- Graphing y =:
- ctg(x)
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Identical expressions
- ctg(x)=x/ zero . two hundred and thirty-four
- ctg(x) equally x divide by 0.234
- ctg(x) equally x divide by zero . two hundred and thirty minus four
- ctgx=x/0.234
- ctg(x)=x divide by 0.234
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Similar expressions
- ctg(x/7)=-4/7
- 5tgx-3ctgx+14=0
ctg(x)=x/0.234 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
x
cot(x) = -----
/117\
|---|
\500/
$$\cot{\left(x \right)} = \frac{x}{\frac{117}{500}}$$
Detail solution
Given the equation
$$\cot{\left(x \right)} = \frac{x}{\frac{117}{500}}$$
transform
$$- \frac{500 x}{117} + \cot{\left(x \right)} - 1 = 0$$
$$- \frac{x}{\frac{117}{500}} + \cot{\left(x \right)} - 1 = 0$$
Do replacement
$$w = \cot{\left(x \right)}$$
Move free summands (without w)
from left part to right part, we given:
$$w - \frac{500 x}{117} = 1$$
Move the summands with the other variables
from left part to right part, we given:
$$w = \frac{500 x}{117} + 1$$
We get the answer: w = 1 + 500*x/117
do backward replacement
$$\cot{\left(x \right)} = w$$
substitute w:
$$\cot{\left(x \right)} = \frac{x}{\frac{117}{500}}$$
transform
$$- \frac{500 x}{117} + \cot{\left(x \right)} - 1 = 0$$
$$- \frac{x}{\frac{117}{500}} + \cot{\left(x \right)} - 1 = 0$$
Do replacement
$$w = \cot{\left(x \right)}$$
Move free summands (without w)
from left part to right part, we given:
$$w - \frac{500 x}{117} = 1$$
Move the summands with the other variables
from left part to right part, we given:
$$w = \frac{500 x}{117} + 1$$
We get the answer: w = 1 + 500*x/117
do backward replacement
$$\cot{\left(x \right)} = w$$
substitute w: