Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation x^2+2x+1=0
-
Equation cos(x)+1=0
- Equation 1/3x+20=1/13x-29
- Equation 25*x^2-400*x=0
- Express {x} in terms of y where:
- -5*x-7*y=16
- -7*x+13*y=-10
- -15*x+6*y=-1
- -2*x+15*y=14
-
Identical expressions
- abs(x+ three)= two
- abs(x plus 3) equally 2
- abs(x plus three) equally two
- absx+3=2
-
Similar expressions
- abs(x-3)=2
- abs(abs(x)+3)=4+x
abs(x+3)=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 3 \geq 0$$
or
$$-3 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 3\right) - 2 = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{1} = -1$$
2.
$$x + 3 < 0$$
or
$$-\infty < x \wedge x < -3$$
we get the equation
$$\left(- x - 3\right) - 2 = 0$$
after simplifying we get
$$- x - 5 = 0$$
the solution in this interval:
$$x_{2} = -5$$
The final answer:
$$x_{1} = -1$$
$$x_{2} = -5$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 3 \geq 0$$
or
$$-3 \leq x \wedge x < \infty$$
we get the equation
$$\left(x + 3\right) - 2 = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{1} = -1$$
2.
$$x + 3 < 0$$
or
$$-\infty < x \wedge x < -3$$
we get the equation
$$\left(- x - 3\right) - 2 = 0$$
after simplifying we get
$$- x - 5 = 0$$
the solution in this interval:
$$x_{2} = -5$$
The final answer:
$$x_{1} = -1$$
$$x_{2} = -5$$
Sum and product of roots
[src]
sum
-5 - 1
$$-5 - 1$$
=
-6
$$-6$$
product
-5*(-1)
$$- -5$$
=
5
$$5$$
5