Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation а^-12×(-4а^7)^2
-
Equation tgx=0
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Equation sqrt(X^2-4X+4)-1=sqrt((3X-5)(3-X))
- Equation tg(x)(ctg(x)-cos(x))=2sin(2x)^2
- Express {x} in terms of y where:
- 15*x-15*y=16
- 9*x+18*y=6
- (x^2+y^2-1)^3+x^2*y^3=0
- -1*x-19*y=-10
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Identical expressions
- а^- twelve ×(-4а^ seven)^ two
- а to the power of minus 12×( minus 4а to the power of 7) squared
- а to the power of minus twelve ×( minus 4а to the power of seven) to the power of two
- а-12×(-4а7)2
- а-12×-4а72
- а^-12×(-4а⁷)²
- а to the power of -12×(-4а to the power of 7) to the power of 2
- а^-12×-4а^7^2
-
Similar expressions
- а^-12×(4а^7)^2
- а^+12×(-4а^7)^2
а^-12×(-4а^7)^2 equation
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The solution
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2 / 7\ \-4*a / -------- = 0 12 a
$$\frac{\left(- 4 a^{7}\right)^{2}}{a^{12}} = 0$$
Detail solution
Expand the expression in the equation
$$\frac{\left(- 4 a^{7}\right)^{2}}{a^{12}} = 0$$
We get the quadratic equation
$$16 a^{2} = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$a_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$a_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 16$$
$$b = 0$$
$$c = 0$$
, then
Because D = 0, then the equation has one root.
$$a_{1} = 0$$
$$\frac{\left(- 4 a^{7}\right)^{2}}{a^{12}} = 0$$
We get the quadratic equation
$$16 a^{2} = 0$$
This equation is of the form
a*a^2 + b*a + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$a_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$a_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 16$$
$$b = 0$$
$$c = 0$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (16) * (0) = 0
Because D = 0, then the equation has one root.
a = -b/2a = -0/2/(16)
$$a_{1} = 0$$
Vieta's Theorem
rewrite the equation
$$\frac{\left(- 4 a^{7}\right)^{2}}{a^{12}} = 0$$
of
$$a^{3} + a b + c = 0$$
as reduced quadratic equation
$$a^{2} + b + \frac{c}{a} = 0$$
$$a^{2} = 0$$
$$a^{2} + a p + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$a_{1} + a_{2} = - p$$
$$a_{1} a_{2} = q$$
$$a_{1} + a_{2} = 0$$
$$a_{1} a_{2} = 0$$
$$\frac{\left(- 4 a^{7}\right)^{2}}{a^{12}} = 0$$
of
$$a^{3} + a b + c = 0$$
as reduced quadratic equation
$$a^{2} + b + \frac{c}{a} = 0$$
$$a^{2} = 0$$
$$a^{2} + a p + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$a_{1} + a_{2} = - p$$
$$a_{1} a_{2} = q$$
$$a_{1} + a_{2} = 0$$
$$a_{1} a_{2} = 0$$