Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2-6x+5=0
- Equation x^2+y^2=9
-
Equation 2*sin(x)+1=0
- Equation (3x−36)⋅(x+8)=0
- Express {x} in terms of y where:
- 12*x-3*y=-2
- 5*x+4*y=7
- 14*x+1*y=3
- 16*x+16*y=-4
-
Identical expressions
- 9x- five *|-x- eleven |
- 9x minus 5 multiply by module of minus x minus 11|
- 9x minus five multiply by module of minus x minus eleven |
- 9x-5|-x-11|
-
Similar expressions
- 9x-5*|+x-11|
- 9x-5*|-x+11|
- 9x+5*|-x-11|
9x-5*|-x-11| equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 11 \geq 0$$
or
$$-11 \leq x \wedge x < \infty$$
we get the equation
$$9 x - 5 \left(x + 11\right) = 0$$
after simplifying we get
$$4 x - 55 = 0$$
the solution in this interval:
$$x_{1} = \frac{55}{4}$$
2.
$$x + 11 < 0$$
or
$$-\infty < x \wedge x < -11$$
we get the equation
$$9 x - 5 \left(- x - 11\right) = 0$$
after simplifying we get
$$14 x + 55 = 0$$
the solution in this interval:
$$x_{2} = - \frac{55}{14}$$
but x2 not in the inequality interval
The final answer:
$$x_{1} = \frac{55}{4}$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x + 11 \geq 0$$
or
$$-11 \leq x \wedge x < \infty$$
we get the equation
$$9 x - 5 \left(x + 11\right) = 0$$
after simplifying we get
$$4 x - 55 = 0$$
the solution in this interval:
$$x_{1} = \frac{55}{4}$$
2.
$$x + 11 < 0$$
or
$$-\infty < x \wedge x < -11$$
we get the equation
$$9 x - 5 \left(- x - 11\right) = 0$$
after simplifying we get
$$14 x + 55 = 0$$
the solution in this interval:
$$x_{2} = - \frac{55}{14}$$
but x2 not in the inequality interval
The final answer:
$$x_{1} = \frac{55}{4}$$
Sum and product of roots
[src]
sum
55/4
$$\frac{55}{4}$$
=
55/4
$$\frac{55}{4}$$
product
55/4
$$\frac{55}{4}$$
=
55/4
$$\frac{55}{4}$$
55/4