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(6x+2)x-(2x-1)(3x+2)=3 equation

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Numerical solution:

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The solution

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(6*x + 2)*x - (2*x - 1)*(3*x + 2) = 3
$$x \left(6 x + 2\right) - \left(2 x - 1\right) \left(3 x + 2\right) = 3$$
Detail solution
Given the equation:
(6*x+2)*x-(2*x-1)*(3*x+2) = 3

Expand expressions:
2*x + 6*x^2 - (2*x - 1)*(3*x + 2) = 3

2*x + 6*x^2 + 2 - x - 6*x^2 = 3

Reducing, you get:
-1 + x = 0

Move free summands (without x)
from left part to right part, we given:
$$x = 1$$
We get the answer: x = 1
The graph
Sum and product of roots [src]
sum
1
$$1$$
=
1
$$1$$
product
1
$$1$$
=
1
$$1$$
1
Rapid solution [src]
x1 = 1
$$x_{1} = 1$$
x1 = 1
Numerical answer [src]
x1 = 1.0
x1 = 1.0