(6x+2)x-(2x-1)(3x+2)=3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
(6*x+2)*x-(2*x-1)*(3*x+2) = 3
Expand expressions:
2*x + 6*x^2 - (2*x - 1)*(3*x + 2) = 3
2*x + 6*x^2 + 2 - x - 6*x^2 = 3
Reducing, you get:
-1 + x = 0
Move free summands (without x)
from left part to right part, we given:
$$x = 1$$
We get the answer: x = 1
Sum and product of roots
[src]
$$1$$
$$1$$
$$1$$
$$1$$