Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 4-6*(x+2)=3-5*x
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Equation 1/(x-3)^2-3/(x-3)-4=0
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Equation x^2-2x+1=0
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Equation 3(x+3)=2x+5
- Express {x} in terms of y where:
- 2*x+13*y=19
- 17*x-20*y=6
- 5*x-13*y=17
- -9*x-1*y=6
- Derivative of:
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6x-8
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Identical expressions
- 6x- eight =5x- three (x- four)
- 6x minus 8 equally 5x minus 3(x minus 4)
- 6x minus eight equally 5x minus three (x minus four)
- 6x-8=5x-3x-4
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Similar expressions
- 6x-8=5x+3(x-4)
- (x-7)(x-3)(x-4)=(x-5)(x-3)(x-4)
- 6x-8=5x-3(x+4)
- sqrt(6*x-8)=sqrt(3*x+3)
- 6x+8=5x-3(x-4)
6x-8=5x-3(x-4) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$6 x = 2 x + 20$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = 20$$
Divide both parts of the equation by 4
We get the answer: x = 5
6*x-8 = 5*x-3*(x-4)
Expand brackets in the right part
6*x-8 = 5*x-3*x+3*4
Looking for similar summands in the right part:
-8 + 6*x = 12 + 2*x
Move free summands (without x)
from left part to right part, we given:
$$6 x = 2 x + 20$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = 20$$
Divide both parts of the equation by 4
x = 20 / (4)
We get the answer: x = 5
Sum and product of roots
[src]
sum
5
$$\left(5\right)$$
=
5
$$5$$
product
5
$$\left(5\right)$$
=
5
$$5$$
The graph