Move right part of the equation to left part with negative sign.
The equation is transformed from 5x2=40x−80 to 5x2−(40x−80)=0 This equation is of the form ax2+bx+c=0 A quadratic equation can be solved using the discriminant The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D=b2−4ac is the discriminant. Because a=5 b=−40 c=80 , then D=b2−4ac= (−1)5⋅4⋅80+(−40)2=0 Because D = 0, then the equation has one root.
x = -b/2a = --40/2/(5)
x1=4
Vieta's Theorem
rewrite the equation 5x2=40x−80 of ax2+bx+c=0 as reduced quadratic equation x2+abx+ac=0 x2−8x+16=0 px+x2+q=0 where p=ab p=−8 q=ac q=16 Vieta Formulas x1+x2=−p x1x2=q x1+x2=8 x1x2=16