5x-4(6-7x)-3(4x+3)=2 equation
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The solution
Detail solution
Given the linear equation:
5*x-4*(6-7*x)-3*(4*x+3) = 2
Expand brackets in the left part
5*x-4*6+4*7*x-3*4*x-3*3 = 2
Looking for similar summands in the left part:
-33 + 21*x = 2
Move free summands (without x)
from left part to right part, we given:
$$21 x = 35$$
Divide both parts of the equation by 21
x = 35 / (21)
We get the answer: x = 5/3
Sum and product of roots
[src]
$$\frac{5}{3}$$
$$\frac{5}{3}$$
$$\frac{5}{3}$$
$$\frac{5}{3}$$