Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 4-6*(x+2)=3-5*x
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Equation 1/(x-3)^2-3/(x-3)-4=0
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Equation x^3=27
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Equation tg(x)=1
- Express {x} in terms of y where:
- 2*x+13*y=19
- 17*x-20*y=6
- 5*x-13*y=17
- -11*x+15*y=7
- Graphing y =:
- 5x-4
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Identical expressions
- 5x- four = three +2x
- 5x minus 4 equally 3 plus 2x
- 5x minus four equally three plus 2x
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Similar expressions
- (x-4)/3+(2(x+1))/4-1=(5(x-3))/2+2x-(11x+43)/6
- 5x-4=3-2x
- (x-1)^3+(2x+3)^3=27x^3+8
- x^2+x^2+x^2+2*x^2+4*x+5*x-4-3=0
- 5x+4=3+2x
5x-4=3+2x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$5 x = 2 x + 7$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = 7$$
Divide both parts of the equation by 3
We get the answer: x = 7/3
5*x-4 = 3+2*x
Move free summands (without x)
from left part to right part, we given:
$$5 x = 2 x + 7$$
Move the summands with the unknown x
from the right part to the left part:
$$3 x = 7$$
Divide both parts of the equation by 3
x = 7 / (3)
We get the answer: x = 7/3
Sum and product of roots
[src]
sum
7/3
$$\frac{7}{3}$$
=
7/3
$$\frac{7}{3}$$
product
7/3
$$\frac{7}{3}$$
=
7/3
$$\frac{7}{3}$$
7/3