5x-4y=20 equation
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The solution
Detail solution
Given the linear equation:
5*x-4*y = 20
Looking for similar summands in the left part:
-4*y + 5*x = 20
Move the summands with the other variables
from left part to right part, we given:
5x=4y+20Divide both parts of the equation by 5
x = 20 + 4*y / (5)
We get the answer: x = 4 + 4*y/5
4*re(y) 4*I*im(y)
x1 = 4 + ------- + ---------
5 5
x1=54re(y)+54iim(y)+4
x1 = 4*re(y)/5 + 4*i*im(y)/5 + 4
Sum and product of roots
[src]
4*re(y) 4*I*im(y)
4 + ------- + ---------
5 5
54re(y)+54iim(y)+4
4*re(y) 4*I*im(y)
4 + ------- + ---------
5 5
54re(y)+54iim(y)+4
4*re(y) 4*I*im(y)
4 + ------- + ---------
5 5
54re(y)+54iim(y)+4
4*re(y) 4*I*im(y)
4 + ------- + ---------
5 5
54re(y)+54iim(y)+4
4 + 4*re(y)/5 + 4*i*im(y)/5